Let V be the volume of the pyramid of height 11 whose base is a square of side length 6. Find a formula for the area A of the horizontal cross section at a height y.

Base area = 36

Volume of the pyramid = 132

Step-by-step explanation:

Volume of a pyramid = Base Area × Height/3

Base area = Length × Length (since base of the pyramid is a square)

Given the side length of the square = 6

Base area = 6×6

Base area = 36

Given height of pyramid =11

Volume of the pyramid = 36×11/3

Volume of the pyramid = 12×11

Volume of the pyramid = 132

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

ok

step-by-step explanation: