Micah is 4 more than twice Angela’s age. The sum of their ages is 40. Set up the problem, Write an equation, Solve the equation, Determine how old Micah and Angela are.

Angela is 12 and Micah is 28.

Step-by-step explanation:

So, the problem tells us that Micah is four more than twice Angel's age, and the sum of both their ages is 40. So, if we use a to stand for Angela's age and m to stand for Micah's age, we can safely assume our equation will look like this:

(a × 2) + 4 = m. And once that is figured out, we use a + m = 40.

For right now, we can start just randomly entering in numbers for a. Let's try 10, for example.

(10 × 2) + 4 = 24.

But does 10 + 24 = 40? No, it equals 34. So we go higher.

(12 × 2) + 4 = 28.

Does 12 + 28 = 40? Yes, yes it does.

So we can say with all certainty that Micah is 28 years old, and Angela is 12.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: