Which lines are perpendicular to the line y - 1= 1(x+2)? Check all that apply y2= -36% -4)

y-5=9(x - 11)

• y=-3x-2/

y = 1x-2

3x + y=7

) Intro

Done

Step-by-step explanation:

Given the line y-1 = 1(x+2), in order to know the line that is perpendicular to the given line, we will first find the slope of the known line.

The standard form of equation of a line is expressed as y = mx+c

m is the slope

c is the intercept

Rewrite the equation given

y-1 = 1(x+2)

y-1 = x+2

y = x+2+1

y = x+3

Comparing to the standard form, the slope m = 1.

For two lines to be perpendicular, the product of their slope must be -1 i.e mM = -1

Substitute

1(M) = -1

M = -1

For us to know the line that is perpendicular to the given line, its slope must be -1.

Since none of the equation has a slope of -1, hence none of the lines are perpendicular to the line y - 1= 1(x+2).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐