What is Which situation can be represented by this equation? Drag the yellow star to indicate which one you believe is the answer 350 - 15x = 200 - 10x

Sam’s Jetski rental charges $350 to rent a jetski plus $15 per hour. Brian’s Jetski rental charges $200 to rent a jetski plus $10 per hour

Steven has an account with $350 in it and he withdrawals $15 per day. Jessica has an account with $200 and withdrawals $10 per day.

Water tank A has 350 gallons of water and is losing 10 gallons per minute. Water tank B has 200 gallons of water and is losing 15 gallons per minute

Tree A has a height of 350 centimeters and is growing at a rate of 15 cm per day. Tree B has a height of 200 centimeters and is growing at a rate of 10 centimeters per day

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west