One out of every 119 tax returns that a tax auditor examines requires an audit. Find the probability that (a) the first return requiring an audit is the 25th return the tax auditor examines, (b) the first return requiring an audit is the first or second return the tax auditor examines, and (c) none of the first five returns the tax auditor examines require an audit.

A) 0.00686

B) 0.01673

C) 0.99587

Step-by-step explanation:

For this question, we are interested in the first success and we will Thus make use of geometric probability distribution.

It goes by the formula;

P(x) = [(1 - p)^(x - 1)]p

We are told that One out of every 119 tax returns that a tax auditor examines requires an audit.

Thus; p = 1/119 = 0.0084

A) Probability that the first return requiring an audit is the 25th return the tax auditor examines is given by;

P(25) = [(1 - 0.0084)^(25 - 1)]0.0084

P(25) = 0.00686

B) Probability the first requiring an audit is the first or second return the tax auditor examines, is;

P(1 or 2) = P(1) + P(2)

P(1) = [(1 - 0.0084)^(1 - 1)]0.0084

P(1) = 0.0084

P(2) = [(1 - 0.0084)^(2 - 1)]0.0084

P(2) = 0.00833

Thus;

P(1 or 2) = 0.0084 + 0.00833

P(1 or 2) = 0.01673

C) Probability that none of the first five returns the tax auditor examines require an audit is given by;

P(X > 5) = 1 - P(X ≤ 5)

Now,

P(X ≤ 5) is expressed as;

P(X ≤ 5) = P(1) + P(2) + P(3) + P(4) + P(5)

We know P(1) & P(2) already. Let's find P(3), P(4) and P(5)

P(3) = [(1 - 0.0084)^(3 - 1)]0.0084

P(3) = 0.00826

P(4) = [(1 - 0.0084)^(4 - 1)]0.0084

P(4) = 0.00819

P(5) = [(1 - 0.0084)^(5 - 1)]0.0084

P(5) = 0.00812

P(X ≤ 5) = 0.0084 + 0.00833 + 0.00826 + 0.00819 + 0.00812

P(X ≤ 5) = 0.00413

P(X > 5) = 1 - 0.00413

P(X > 5) = 0.99587

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

i can answer this if i have the answer choices