TT Consider 3 trials, each having the same probability of success. Let X denote the

total number of successes in these trials. If E(X) = 1.8, the smallest possible value of Pr{X = 3}?

Construct a probability scenario that results in Pr{X = 3} having the stated value.

(Hint: For part (b), you might start by letting U be a uniform random variable on (0,1) and then defining the trials in terms of the value of U.)

Solve using hint

The smallest possible value of Pr{X = 3} is  U = 0

Step-by-step explanation:

  The number of trial is  n = 3

  The mean is  E(X) = 1.8

Gnerally given that every probability value lies between 0  and 1 ,

let U be the smallest possible value of  Pr{X = 3}

it then mean that U= 0 because in the range which probability values can take , the smallest value is  zero

So

     The smallest possible value of Pr{X = 3} is  U = 0

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

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