Consider the quadratic function f(x)AxBxC, where A, B, and C are real numbers with A0. Show that when the Mean Value Theorem is applied to f on the interval [a, b], the number c guaranteed by the theorem is the midpoint of the interval. Apply the Mean Value Theorem to f(x) on [a, b]. First, find .

the probability is 0

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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homozygous. one is homozygous, while two is heterozygous.

95.03 is the answer. hope this !