Please help if you know how to do this, thanks

9514 1404 393

  4) y = -3(x+2)^2 +4; y = -3x^2-12x-8; ABC=(-3, -12, -8)

  5) y = 0.5(x-1)^2-2; y = 0.5x^2-x-1.5; (h,k) = (1, -2)

  6) y = -0.3(x+2)^2-6; y = -0.3x^2-1.2x-7.2; (h,k) = (-2, -6)

Step-by-step explanation:

Writing a quadratic equation through a set of points is most easily done using the regression function of a graphing calculator or spreadsheet.

4) see the first attachment

  y = -3(x+2)^2 +4 . . . vertex form

  y = -3x^2 -12x -8 . . . standard form (A, B, C) = (-3, -12, -8)

__

5) see the second attachment

  y = 0.5(x -1)^2 -2 . . . vertex form; vertex = (1, -2)

  y = 0.5x^2 -x -1.5 . . . standard form

__

6) see the third attachment

  y = -0.3(x +2)^2 -6 . . . vertex form; vertex = (-2, -6)

  y = -0.3x^2 -1.2x -7.2 . . . standard form

_____

Doing this without machine help requires you pick a form of the equation you want, fill in the x- and y-values for three of the given points, then solve the resulting equations for the unknown parameters. Usually, we use the form ...

  y = ax^2 +bx +c

which will result in three linear equations for a, b, c. Those can be solved by any of the usual methods.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.