'Cause I, I, I'm in the stars tonight So watch me bring the fire and set the night alight (Hey)
Shining through the city with a little funk and soul
So I'ma light it up like dynamite, woah-oh-oh

[Verse 2: V, RM]
Bring a friend, join the crowd, whoever wanna come along
Word up, talk the talk, just move like we off the wall
Day or night, the sky's alight, so we dance to the break of dawn (Hey)
Ladies and gentlemen, I got the medicine so you should keep ya eyes on the ball, huh

[Pre-Chorus: Suga, Jimin, RM]
This is getting heavy, can you hear the bass boom? I'm ready (Woo-hoo)
Life is sweet as honey, yeah, this beat cha-ching like money, huh
Disco overload, I'm into that, I'm good to go
I'm diamond, you know I glow up
Let's go

[Chorus: Jungkook, V]
'Cause I, I, I'm in the stars tonight
So watch me bring the fire and set the night alight (Hey)
Shining through the city with a little funk and soul
So I'ma light it up like dynamite, woah-oh-oh

[Post-Chorus: Jungkook, Jimin, Jin]
Dyn-na-na-na, na-na-na-na-na, na-na-na, life is dynamite
Dyn-na-na-na, na-na-na-na-na, na-na-na, life is dynamite
Shining through the city with a little funk and soul
So I'ma light it up like dynamite, woah-oh-oh

[Bridge: Jungkook, j-hope, Jimin, V]
Dyn-na-na-na, na-na, na-na, ayy
Dyn-na-na-na, na-na, na-na, ayy
Dyn-na-na-na, na-na, na-na, ayy
Light it up like dynamite
Dyn-na-na-na, na-na, na-na, ayy
Dyn-na-na-na, na-na, na-na, ayy
Dyn-na-na-na, na-na, na-na, ayy
Light it up like dynamite

[Chorus: Jimin, Jungkook, Jin]
'Cause I, I, I'm in the stars tonight
So watch me bring the fire and set the night alight
Shining through the city with a little funk and soul
So I'ma light it up like dynamite

(This is ah) 'Cause I, I, I'm in the stars tonight
So watch me bring the fire and set the night alight (Alight, oh)
Shining through the city with a little funk and soul
So I'ma light it up like dynamite, woah-oh-oh (Light it up like dynamite)

[Post-Chorus: Jungkook, Jimin, V]
Dyn-na-na-na, na-na-na-na-na, na-na-na, life is dynamite (Life is dynamite)
Dyn-na-na-na, na-na-na-na-na, na-na-na, life is dynamite (Oh)
Shining through the city with a little funk and soul
So I'ma light it up like dynamite, woah-oh-oh

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

i agree because i see the other persons thinking is clear