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Mathematics, 21.10.2020 06:01 jkirby29

Choices: (x + 0, y -12)
(x + 8, y - 6)
(x + 1, y - 13)
(x - 7, y - 3)
(x + 10, y + 0)


Choices:

(x + 0, y -12)
(x + 8, y - 6)
(x + 1, y - 13)
(x - 7, y - 3)
(x + 10, y + 0)

ansver
Answers: 2

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Choices: (x + 0, y -12)
(x + 8, y - 6)
(x + 1, y - 13)
(x - 7, y - 3)
(x +...
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