there are 35 students in art class and 57 students in dance class. Find the number of students who are either in art class or in dance class

hope it helps you

Step-by-step explanation:

Let

A be the set of students in art class

B be the set of students in dance class

n(A) = 35    

n(B) = 57      

a) When 2 classes meet at different hours and n(A ∩ B) = 12 we have:

n(A ∪ B) = n(A) + n(B) - n(A ∩ B) = 35 + 57 - 12 = 80

b) When two classes meet at the same hour we have A∩B = ∅ that is n(A ∩ B) = 0 and

n(A ∪ B) = n(A) + n(B) - n(A ∩ B) = n(A) + n(B)  = 35 + 57 = 92

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

step-by-step explanation: