A construction company orders tile flooring for the kitchen and three bathrooms of a new home. The kitchen floor measures 48 square feet. Two bathrooms have floors that each measure square feet. The third bathroom floor measures square feet. If the tile costs $2.39 per square foot, what's the least amount of money, to the nearest cent, the company spends on tile for all three bathrooms

Step-by-step explanation:

The question is incomplete. Let us assume the two bathrooms have floors that each measure 24 square feet and third bathroom floor measures 18 square feet.

For the two bathrooms, the total area will be 2*24 = 48 square feet

Since the third bathroom measures 18 square feet, the total square feet for the  3 bathrooms is equal to 48sq. ft + 18 sq.ft = 64sq. ft

If the tile costs $2.39 per square foot, then the amount that 64sq. ft tiles will cost is expressed as:

1 sq. ft = $2..39

64sq.f = $x

Cross multiply:

1*x = 2.39* 64

x = $152.96

Hence the amount that the company's spent on tiles for the three bathrooms will be 15296 cents.

Note that the dimensions of bathrooms were assumed. You can follow the same procedure for any dimension given.

3+x

step-by-step explanation: