The cost to build an amusement park ride by a certain contractor is represented by the function: Cost = 2*x2 – 10/x + 36*y + 25 where x is the number of people able to be on the ride at once. For what value of x would unit cost be minimized? What is the minimum cost for this number of passengers? Show mathematically that the value found is truly a minimum and discuss whether this solution is feasible.

The minimum cost for this number of passengers is Rs.36.05

Step-by-step explanation:

The cost to build an amusement park ride by a certain contractor is represented by the function:

x : Number of people able to be on the ride at once.

Differentiate the function w.r.t x

x=-1.3572

Differentiate the function w.r.t y

Minimum cost =

Minimum cost =

Minimum cost = 36.05

Hence the minimum cost for this number of passengers is Rs.36.05

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b