A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet away from the player. The height $y$ (in feet) of a second hockey puck is modeled by $y=x\left(0.15-0.001x\right)$ , where $x$ is the horizontal distance (in feet). Compare the distances traveled by the hockey pucks before hitting the ground.

Second puck travels farther

Step-by-step explanation:

Maximum height of first puck = 3 feet

The height of a second hockey puck is modeled by:

To find maximum height of second puck

Equate the derivative equals to 0

0.15-0.002x=0

75 = x

At x = 75

So, The maximum height of second puck is greater than  first puck

So, Second puck travels farther

1 is b and 2 is d

step-by-step explanation: