The 6th graders brought in 56 boxes of tissues 48 pads of loose leaf and 16 rolls of toilet paper. The t acher wants to divide the materials into the greatest amount of containers but wants each container to look the same how many containers can they fill how many of each item will be inside the containers

The greatest amount of containers with each container to looking the same is 8 containers.

Step-by-step explanation:

We have:

56 boxes of tissues

48 pads of loose leaf

16 rolls of toilet paper.

To find the greatest amount of containers with each container to looking the same we apply the greatest common factor method

Step 1

We list the factors of 16, 48 and 56

The factors of 16 are: 1, 2, 4, 8, 16

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The greatest common factor is 8.

Hence, the greatest amount of containers with each container to looking the same is 8 containers.

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step-by-step explanation:

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the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2