Container A and container B have leaks. Container A has 800ml of water, and is leaking 6 ml per minute. Container B has1000 ml, and is leaking 10 ml per minute. How many minutes, m, will it take for the two containers to have the same amount of water?

50 minutes

Step-by-step explanation:

First set up an inequality to find you answer like

800 - 6x = 1000 - 10x

then subtract 800 from both sides leaving you with

-6x = 200 - 10 x

Then add 10 x to both sides giving you

4x = 200

The simplify from here by dividing 200 by 4

200/4 = 50 giving you your answer

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

sorry not sure

step-by-step explanation: