The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x): A graph with two linear functions; f of x passes through 5, 0 and 10, 10, and g of x passes through negative 3, 0 and 2, 10.

Part A: Describe two types of transformations that can be used to transform f(x) to g(x). (2 points)

Part B: Solve for k in each type of transformation. (4 points)

Part C: Write an equation for each type of transformation that can be used to transform f(x) to g(x). (4 points)

Part A:

1) g(x)= f(x) + K

2) g(y) = f(y) + K

Part B:

1) k = - 3y(1/9) - 2

2) K = 0

Part C:

1) g(x) = f(x) - 3×y×(1/9) - 2

2) g(y) = f(y)

Step-by-step explanation:

The coordinates of the points on the linear function  f(x) are (5, 0) and (10, 10)

The coordinates of the points on the linear function  g(x) are (3, 0) and (2, 10)

Therefore, we have;

The slope of f(x) = (10 - 0)/(10 - 5) = 2

The slope of g(x) = (10 - 0)/(2 - 3) = -10

The equation of f(x) is y = 2x - 10

The equation of g(x) is y = -10x + 30

2x - 10 = -10x + 30

x = 40/12 = 10/3, y = 20/3 - 10 = -10/3

Part A

Therefore,

1) g(x)= f(x) + K

2) g(y) = f(y) + K

Part B:

From the slope of the lines, we have;

1) g(x)= f(x) - y(1/2) - 2 +  y(1/-10) = f(x) - 3y(1/9) - 2

g(x) = f(x) - 3y(1/9) - 2

k = - 3y(1/9) - 2

2) g(y) = f(y), K = 0

Part C;

1) g(x) = f(x) - 3×y×(1/9) - 2

2) g(y) = f(y).

Trust me leave this page.

step-by-step explanation:

the one underneath me does not work.

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )

plz mark brainliest i took the test