Write the equation of a line that is perpendicular to y= 3x-2 and that passes through the point (-9,5)

Ans: y = (-1/3)x + 2

Step-by-step explanation:

Perpendicular lines have slopes whose product is -1.  The slope given in

y = 3x - 2

is -3.

The slope of the perpendicular line will be m, and m needs to satisfy the equation

3 * m = -1

Hence m = -1/3.

Our perpendicular line is thus

y = (-1/3)x + b

for some constant b.

We are told that the perpendicular line goes through the point (-9,5).  If so, then the following must hold:

5 = (-1/3)(-9) + b

= 3 + b

b = 2

Ans: y = (-1/3)x + 2

ian gonna lie that is way to much

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: