Consider matrix A. What matrix results from the elementary row operations represented by −2R2+3R1?

Step-by-step explanation:

Given the matrix

Before we can get the resulting matrix after the elementary operation, we need to get the new second row using the formula −2R2+3R1?

when R1= -3, R2 = 8

−2R2+3R1? = −2(8)+3(-3)

−2(8)+3(-3) = -16-9

−2(8)+3(-3) = -25

R1= 5, R2 = -1

−2R2+3R1? = −2(-1)+3(5)

−2(-1)+3(5) = 2-15

−2(-1)+3(5) = -13

when R1= 2, R2 = 3

−2R2+3R1? = −2(3)+3(2)

−2(3)+3(2) = -6-6

−2(3)+3(2) = 0

Hence the new R2 are -25, -13, 0

The resulting matrix will be:

answer:

c 60% on edg

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.