A line passes through the points (-2, 9) and (1, 3). provide work for calculating the slope and y-intercept. Then, write the equation for the line in slope-intercept form.

Finding slope: y2-y1/x2-x1

3-9/1+2

=-6/2

Divide 2 from both

=-3/1 or -3

Slope= -3

Finding y-intercept= y=mx+b

Choose any point on the line to plug in the x and the y then plug in the slope.

I choose (1,3)

3=-3×1+b

3=-3+b

Add 3 to both sides

6=b

Y-intercept=6

Equation: y=-3x+6

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: