Y = –6x+2 –12x – 2y = –4
How many solutions does this linear system have?

one solution: (0, 0)
one solution: (1, –4)
no solution
infinite number of solutions

infinite number of solutions

Step-by-step explanation:

y = -6x + 2 . . . . . . . . (1)

-12x - 2y = -4 . . . . . . (2)

Putting (1) into (2), we have

-12x - 2(-6x + 2) = -4

-12x + 12x - 4 = -4

-4 = -4

Therefore, the system has infinite number of solutions.

I hope this helps you! :3 :)

6 spoons of sugar for every 21 cups of flour

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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