Aman has two more nickels than dimes. he has $1.15 in all. how many coins of each kind does he have?
which equation can be used to solve the problem?

5x + 10(x + 2) = 115
5(x + 2) + 10x = 115
x + x + 2 = 115

5(x +2) + 10x = 115

Number of nickels = 9 and dimes = 7

Step-by-step explanation:

Let the number of nickels a man has = y

and dimes = x

Then by the statement of the question we can form the equation as

y = x + 2(1)

(.05)y + (.10)x = 1.15(2)

By multiplying equation 2 by 100

5y + 10x = 115(3)

Now we put the value of y from equation 1 in the equation 3

5(x + 2) + 10x = 115

5x + 10 + 10x = 115

15x + 10 = 115

15x = 105

x = 7

y = 7 + 2 = 9

Number of nickels = 9 and dimes = 7

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

do you have a picture of the table