Lisa is standing on a dock beside a lake. she drops a rock from her hand into the lake. after the rock hits the surface of the lake, the rock's distance from the lake's surface changes at a rate of −2 inches per second. if lisa holds her hand 6 feet above the lake's surface, how far from lisa's hand is the rock 8 seconds after it hits the surface?

6 feet + 2 inches per second x 8 seconds.

6 feet + 16 inches

7 feet and 4 inches or 88 inches (72 inches + 16 inches)

The distance between Lisa hand and rock is 88 inches.

Step-by-step explanation:

Consider the provided information.

We need to find how far from Lisa's hand is the rock 8 seconds after it hits the surface.

The rock's distance from the lake's surface changes at a rate of −2 inches per second.

In 8 second the distance of rock and surface will be:

Distance = 8×(2) = 16 inches below the surface of lake.

We took positive 2 because distance can't be a negative number.

Lisa holds her hand 6 feet above the lake's surface.

Convert 6 feet into inches.

1 feet = 12 inches

6 feet = 72 inches.

That means the total distance will be:

72+16 = 88 inches.

Hence, the distance between Lisa hand and rock is 88 inches.

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step-by-step explanation: