Mathematics, 22.10.2020 15:01 cmikell124

HELP ME IM LOST :/ In the diagram, QRSTU is a regular pentagon and STVW is
a straight line. PQVW is a part of a regular polygon. Find
the number of sides of the regular polygon.

HELP ME IM LOST :/

In the diagram, QRSTU is a regular pentagon and STVW isa straight line. PQVW i

Answers: 2

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Answer from: mmaglaya1

15 sides

Step-by-step explanation:

Recall the following about interior and exterior angles of polygons.

Interior angles of polygons:

The formula (n - 2)180 gives the sum of the measures of the interior angles of a polygon of n sides.

If we know the number of sides, we can find the sum of the measures of the angles.

Exterior angles of polygons:

The sum of the measures of the exterior angles of a polygon is 360. If the polygon is a regular polygon of n sides, then the measure of each exterior angle is 360/n.

This problem:

QRSTU is a regular pentagon.

The sum of the measures of the sides of a polygon of n sides is

(n - 2)180

For a pentagon, n = 5, so

(n - 2)180 = (5 - 2)180 = (3)180 = 540

The sum of the measures of the angles of pentagon QRSTU is 540.

Since it's a regular polygon, each angle measures 540/5 = 108.

Angles UQR, R, and S are interior angles of the pentagon, so each one measures 108 degrees.

Now look at polygon VQRS. It is a quadrilateral with sides VQ, QR, RS, and SV. The sum of the measures of the angles of a quadrilateral (4 sides; n = 4) is

(n - 2)180 = (4 - 2)180 = 2(180) = 360

m<VQU = 12 (given)

m<UQR = 108

m<VQR = m<VQU + m<UQR = 108 + 12 = 120

The angles of quadrilateral VQRS are <VQR, <R, <S ,and <TVQ. Their sum is 360.

<VQR + m<R + m<S + m<TVQ = 360

We now substitute the angle values we know and solve for m<TVQ.

120 + 108 + 108 + m<TVQ = 360

m<TVQ = 24

<TVQ is an exterior angle of the large polygon of which PQ, QV and VW are sides.

The sum of the measures of the exterior angles of a polygon, one per vertex, is 360. For a regular polygon, all exterior angles are congruent, and the measure of each exterior angle is the sum of the the measures of the exterior angles divided by the number of sides.

$measure~of~an~exterior~angle = \dfrac{sum~of~the~measures~of~the~exterior~angles}{number~of~sides}$

$a = \dfrac{360}{n}$

We know that the measure of an exterior angle is 24 deg.

$24 = \dfrac{360}{n}$

$n = \dfrac{360}{24}$

n = 15

15 sides

Answer from: Keo247

15 sides

This was tough.

Answer from: Quest

The first one minimumi hope my answer you.

Answer from: Quest

-232

step-by-step explanation:

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HELP ME IM LOST :/ In the diagram, QRSTU is a regular pentagon and STVW is
a straight line. PQ...

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