Suppose that a tea company estimates that its monthly cost is C(c) = 500x² + 100x and its monthly revenue is R(2) = -0.6x3 + 700x2 – 400x + 300, where x is in thousands of boxes of tea sold. The profit is the difference between the revenue and the cost. What is the profit function, p(X)? O A. P(x) = 0.6x3- 200x2 + 500x+ - 300

OB. P(x) = -0.6x3 + 1200x2 – 300x + 300

O C. P(x) = -0.6x3 + 200x2 – 500x + 300

D. P(xl = 0.6x3 + 200x2 – 500x + 300

p(x) = 0.6x³ - 200x² + 500x- 300

Step-by-step explanation:

Given the cost function and revenue function as:

C(x) = 500x² + 100x

R(x) = -0.6x³ + 700x² – 400x + 300

To get the profit function:

p(x) = C(x) - R(x)

p(x) = 500x² + 100x -(-0.6x³ + 700x² – 400x + 300)

open the parenthesis

p(x) = 500x² + 100x + 0.6x³ - 700x² + 400x - 300

p(x) = + 0.6x³+500x² - 700x² + 100x+ 400x- 300

p(x) = 0.6x³ - 200x² + 500x- 300

Hence the profit function is expressed as p(x) = 0.6x³ - 200x² + 500x- 300

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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