Question: Two years ago, my age was four times the age of my son, eight years ago my age was ten times the age of my son find the age of my son now This question has already been explained by my friend, but I don't get how she knew she had to get the dad's age in terms of sons age, + 6 to it, and then solve it. Someone please explain

My age is 38 years old

My son is 11 years old

Step-by-step explanation:

Represent my current age with x and my son's current age with y

Two years ago;

Eight years ago:

Simplify both expressions

Add 2 to both sides

Substitute 4y - 6 in the second equation

Collect Like Terms

Divide through by -6

Substitute 11 for y in

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9