The perimeter of a playing field for a certain sport is 214 ft. The field is a rectangle, and the length is 41 ft longer than the width. Find the dimensions The width of the playing field is

(Type an integer or a decimal)

Step-by-step explanation:

Perimeter of a rectangle = 2(L+W)

L is the length of the rectangle:

W is the width of the rectangle.

Given

Perimeter = 214feet

If the length is 41 ft longer than the width, then L = 41+W

Substitute L = 41+W into the formula:

P = 2(L+W)

214 = 2(41+W+W)

214 = 2(41+2W)

214 = 82+4W

4W = 214-82

4W = 132

W = 132/4

W = 33 feet

Since L = 41+W

L = 41+33

L = 74 feet

Hence the dimension of the field is 74ft by 33ft

The width of the playing field is 33feet

my answer is$ 12

step-by-step explanation:

because 15 -2=12