If pqr=tsr what are the congruent corresponding parts

The corresponding parts of a triangle are parts that have the same measurement.

The corresponding parts are: P & T, Q & S and R & R

The given parameter is:

The above congruence equation means that:

Hence, the corresponding parts are:

P & T, Q & S and R & R

The above highlight means that:

Read more about corresponding parts at:

link

The congruent corresponding parts:

∠P≅∠T  (first letter)  , ∠Q≅∠S (second letter), ∠R≅∠R (third letter)

segment PQ ≅ segment  TS , segment  QR≅ segment  SR , segment PR ≅ segment TR.

Step-by-step explanation:

We know that if two triangles area congruent then the corresponding parts area congruent.

Given: ΔPQR ≅ ΔTSR

Then, ∠P≅∠T  (first letter)  , ∠Q≅∠S (second letter), ∠R≅∠R (third letter)

segment PQ ≅ segment  TS , segment  QR≅ segment  SR , segment PR ≅ segment TR.

Hence, the congruent corresponding parts:

∠P≅∠T  (first letter)  , ∠Q≅∠S (second letter), ∠R≅∠R (third letter)

segment PQ ≅ segment  TS , segment  QR≅ segment  SR , segment PR ≅ segment TR.

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺