M(12, 1) is the midpoint of DG. If D is at (6, 5), then where is G?

18, -3

using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

y -5 = (-1/4)(x + 8)

step-by-step explanation: