Write equation in slope intercept form (x=mx+b). Find the slope (x) and the y-intercept (b) of the line

y = (2/3)x - 1

Step-by-step explanation:

By refering the graph, we can see that y-intercept(b) = (a point of the y-axis) which is -1.

the coordiates i have taken:

(-3 , -3) (-3 =x1, -3 =y1)

and

( 3, 1 ) ( 3 = x2, 1 = y2)

To find slope,

slope(m) = rise/run = ( y2 - y1 ) / ( x1 - x2 )

=> ( 1 - (-3) ) / ( 3 - (-3) ) ( negative × negative = positive. Hence the signs are positive. )

=> ( 1 + 3 ) / ( 3 + 3 )

=> 4 / 6

=> 2 / 3 (simplied after numerator and denominator got divided by 2)

now,

b = -1

m = 2/3

x = x (x remains same)

Therefore,

y=> mx + b

by substituting the values, we get,

y=> (2/3)x - 1

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

is this part of a question or something