Tom won $30,000 in the lottery. He put all of it in an account. He let it stay there for 6 years earning a simple
interest of 11%. How much interest did he earn over
those 6 years?

I = $19,800

Step-by-step explanation:

Given a principle of 30,000$, a time of 6 years, and a percent interest of 11%(rate) in simple interest. We can use the simple interest formula to solve this problem.

Simple interest: I = prt.

Where I = interest(money earned), p = principle(starting money), r = rate(as a percentage), and t = time(in respect to years).

I = $6 × 11 % × $30,000

$I = 6 × 0.11 × 30,000

$I = 6 × 3,300

$I = 19,800

I = $19,800

If you are curious about the current amount, just add the principle, and the interest.

current balance = I + p .

current balance = $19,800 + $30,000 .

current balance = $49,800 .

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6