The weight of a batch of pumpkins harvested from a local farm follows a normal distribution with a mean of 20 lb and a standard deviation of 3 lb. Find the probability that a randomly selected pumpkin weighs more than 24 lbs.

The probability that a randomly selected pumpkin weighs more than 24 lbs is 0.091211

Step-by-step explanation:

We solve this using z score formula

z-score is is z = (x-μ)/σ

where x is the raw score = 24lbs

μ is the population mean = 20Ibs

σ is the population standard deviation = 3Ibs

z = 24 - 20/3

z = 1.33333

The Probability value from Z-Table:

P(x ≤ 24) = P(x < 24) = P(z = 1.33333)

= 0.90879

P(x > 24) = 1 - P(x<24)

= 1 - 0.90879

= 0.091211

Therefore, the probability that a randomly selected pumpkin weighs more than 24 lbs is 0.091211

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.