Graph the first five ordered pairs for the sequence given by the formula an = 2+3(n - 1).

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  (1, 2), (2, 5), (3, 8), (4, 11), (5, 14)

Step-by-step explanation:

Put the numbers 1 through 5 in the formula and do the computation:

  n = 1 (first term): 2 + 3(1 -1) = 2

  n = 2 (second term): 2 + 3(2 -1) = 5

  n = 3 (third term): 2 + 3(3 -1) = 8

  n = 4 (fourth term): 2 + 3(4 -1) = 11

  n = 5 (fifth term): 2 + 3(5 -1) = 14

The first 5 ordered pairs are (n, an) = (1, 2), (2, 5), (3, 8), (4, 11), (5, 14).

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Alternatively, you can compare the given formula to the formula for the general term of an arithmetic sequence:

  an = a1 + d(n -1)

Matching features of this formula with the given one, we see that ...

  a1 = 2, d = 3

That is, the first term is 2, and the common difference is 3. We can write down the sequence by starting with 2 and counting by 3s from there:

  2, 5, 8, 11, 14, 17, 20, 23, ...

Each "ordered pair" will consist of (term number, term value). Then the first 5 ordered pairs are ...

  (1, 2), (2, 5), (3, 8), (4, 11), (5, 14)

answer: 4 (:

step-by-step explanation: