M∠1=(2y-7° and m∠3=(y+17)° What is the m∠1 ? What is the m∠2? What is the m∠3? What is the m∠4

∠1 = 41°

∠3 = 41°

∠2 = 49°

∠4 = 49°

Step-by-step explanation:

Given:

∠1 = (2y-7)°

∠3 = (y+17)°

Find:

∠1 = ?

∠2 = ?

∠3 = ?

∠4 = ?

Computation:

∠1 = ∠3

(2y-7)° = (y+17)°

2y - y = 17 + 7

y = 24

So

∠1 = (2y-7)° = 2(24)-7 = 41°

∠3 = (y+17)° = 24+17 = 41°

∠2 = 90 - 41 = 49°

∠4 = 90 - 41 = 49°

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204