Find the area of a parallelogram bounded by the x-axis, the line g(x)=2,the line f(x)=3x, and the line parallel to f(x) passing through (3,-6) It might be helpful to remember that the distance between two points =sqrt(x_2-x_1)^2+(y_2-y_1)^2} and the area of a parallelogram is A=bh A=_ (6,1).

i think the answer is b.

step-by-step explanation:

not 100% sure though.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

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step-by-step explanation: