Polygon ABCD has sides with these lengths: , 5 units; , 4 units; , 4.5 units; and , 7 units. The slope of is 5, the slope of is 0.25, the slope of is -2, and the slope of is 0. The polygon is dilated from point A by a scale factor of 1.2 to form polygon A′B′C′D′. Match the slopes and lengths of the sides of polygon A′B′C′D′ to their values.

⇒ Slope of |A'B'| = Slope of |AB| = 5

     Length of |A'B'| = K × length of |AB|

                               = 1.2 × 5

                               = 6 units

⇒   Slope of |B'C'| = Slope of |BC| = 0.25

     Length of |B'C'| = K × length of |BC|

                               = 1.2 × 4

                               = 4.8 units

⇒   Slope of |C'D'| = Slope of |CD| = -2

     Length of |C'D'| = K × length of |CD|

                               = 1.2 × 4.5

                               = 5.4 units

⇒   Slope of |A'D'| = Slope of |AD| = 0

     Length of |A'D'| = K × length of |AD|

                               = 1.2 × 7

                               = 8.4 units

Step-by-step explanation:

Dilation changes the length of corresponding sides to K times (where K is dilation factor) but it does not affect the slopes of the line segments.

i.e. Slope of primed segments = Slope of corresponding unprimed segments

Length of primed segments = K × length of corresponding unprimed segments

With dilation factor K = 1.2, Calculating for |A'B'| |B'C'| |C'D'| |A'D'|

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm