Find the largest possible rectangular area you can enclose with 96 of fencing. What is the (geometric) significance of the dimensions of this largest possible enclosure?What are the dimensions in meters?What are the dimensions in feet?What is the area in square feet?

Kindly check explanation

Step-by-step explanation:

Given that:

Meter of fencing = 96

The perimeter (p) of a square is given as :

p = 4s ; where s = side length

p = 96

96 = 4s

s = 96/4

s = 24

Hence, the maximum area that can be enclosed = 24² = 576m²

Dimension in meters = (24 * 24)m

Dimension in feet:

1m = 3.28 foot

(3.28 * 24 ; 3.28 * 24) = (78.72, 78.72)fts

Area in square feet:

(78.72ft * 78. 72ft) = 6196.84ft²

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi