Num grupo de 11 pessoas, sendo 5 homens e 6 mulheres, escolhendo-se duas delas aleatoriamente, qual a probabilidade das duas serem do mesmo sexo?

12/5 = -6
This you did I’d the five and twelve and you get negative 6

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form