Data accumulated by the National Climatic Data Center shows that the average wind speed in miles per hour for St. Louis, Missouri is 9.7. Suppose wind measurements are normally distributed for a given geographic location. If 12.2% of the time, the wind speed measurements are more than 11.6 miles per hour, what is the standard deviation of wind speed in St. Louis

Step-by-step explanation:

12.2 % of the time , wind measurement is more than 11.6 miles per hour

77.55 % of the time , wind measurement is less than 11.6 miles per hour

z value for p ( x < .7755 ) = .76

.76 = 11.6 - 9.7 / σ

σ = 2.5  

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

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