Joe has 2 solutions that contain alcohol and is mixing them with each other he uses 500 milliliters less of solution A than solution B Solution A is 14% alcohol and solution B is 19% alcohol how many milliliters of solution B does he use if the resulting mixture has 161 milliliters of pure alcohol

700 milliliters of solution B

Step-by-step explanation:

Joe has 2 solutions that contain alcohol and is mixing them with each other he uses 500 milliliters less of solution A than solution B

A = B - 500

Solution A is 14% alcohol and solution B is 19% alcohol

14%A +19%B = 161 mm

0.14A + 0.19B = 161

Substitute for B - 500 for A in the equation below:

0.14A + 0.19B = 161

0.14(B - 500) + 0.19B = 161

0.14B - 70 + 0.19B = 161

Collect like terms

0.14B + 0.19B = 161 + 70

0.33B = 231

B = 231/0.33

700 milliliters

A = B - 500

A = 700 - 500

A = 200 milliliters

Therefore, he uses 700 milliliters of solution B

60: 45 =12: 9 =4: 3 so the answer is 4: 3