Sherwin wants to attend a two-year college with an annual tuition of $6,425. For his savings plan, he invested $5,000 in an account that earns 3.75% interest He deposits an additional $100 per month for four years. What is the difference between his two-year tuition and the value in his savings account?

Instructions are below.

Step-by-step explanation:

Giving the following information:

Total tuition= 6,425*2= $12,850

First, we need to calculate the future value of the initial investment:

FV= PV*(1+i)^n

PV= 5,000

n= 4*12= 48

i= 0.0375/12= 0.003125

FV= 5,000*1.003125^48

FV= $5,807.81

Now, the future value of the monthly deposit:

FV= {A*[(1+i)^n-1]}/i

A= monthly deposit

FV= {100*[(1.003125^48) - 1]} / 0.003125

FV= $5,170

Total FV= 5,807.81 + 5,170= $10,977.81

Finally, the difference:

Difference= 10,977.81 - 12,850= -$1,872.19

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

part a: 1.08

part b: 27.59