Mathematics, 23.10.2020 17:20 elizabethxoxo3271
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The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y − 80 = 0. The center of the cooling tower is the same as the center of the hyperbola, and the x-axis represents the ground surface.
The diameter at the center of the tower is
meters. The center of the tower is
meters above the ground.
Answers: 1
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The hyperbolic cross section of a cooling tower is given by the equation 4x2 − y2 + 16y −...
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