Angelina wants to prove that vertical angles are congruent. She uses the diagram below to formulate her proof. Angelina has one step wrong in her proof. The steps of her proof are shown below. Mark the step that is INCORRECT.

A.
Linear pairs of angles are complementary, hence, m∠2 + m∠3 = 90°.

B.
Subtracting m∠3 from both sides of the above equation gives m∠2 = m∠4.

C.
In my proof, I used m∠2 + m∠3 = m∠3 + m∠4 to justify linear pairs.

D.
By definition of congruent angles, ∠2 ≅ ∠4. This will show that ∠2 and ∠4 are veritcal angles.

Option (A)

Step-by-step explanation:

Correct proof to prove the vertical angles are congruent :

1). Linear pairs of angles are supplementary.

   m∠2 + m∠3 = m∠3 + m∠4

2). By subtracting m∠3 from both the sides of the above equation.

3). By definition of congruent angles, ∠2 ≅ ∠4. This will show that ∠2 and ∠4 are vertical angles.

Therefore, Option (A) is incorrect in which Angelina showed that linear pairs of angles are complementary.

where is the picture

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.