A person washing the windows of an office building drops a squeegee from a height of 95 feet. How long does it take the squeegee to pass by another window washer working at a height of 20 feet?
The squeegee passes by the other window washer in seconds to the nearest tenth.
seconds. If necessary, round your answer

The squeegee passes by the other window washer in 3.9 seconds to the nearest tenth

Step-by-step explanation:

From the question,

The first person drops a squeegee from a height of 95 feet, to determine how long it takes the squeegee to pass by another person at a height of 20 feet, that is, we are to determine how long it will take the squeegee to travel a height distance of 95 feet - 20 feet

95 feet - 20 feet = 75 feet.

Hence, we are to determine how long it will take the squeegee to travel a height distance of 75 feet.

From one of the equations of motion due to free fall

h = ut + 1/2gt²

Where h is the height

u is the initial velocity

g is the acceleration due to gravity (Take g = 9.8 m/s²)

and t is the time

For the question,

h = 75 feet

u = 0 m/s ( Since the squeegee is dropped from rest)

Therefore

75 = 0(t) + 1/2(9.8)(t²)

75 = 4.9t²

∴ t² = 75/4.9

t² = 15.306

t =√15.306

t = 3.9 secs

Hence,

The squeegee passes by the other window washer in 3.9 seconds to the nearest tenth.

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step-by-step explanation: