APPLICATIONS 4. When at a carnival there are height restrictions to go on each ride. Determine which rides each member of this family can go on by filling out the table below: The Swings: The Twister: h> 24 and h 48 or h42 and h 60 Tracey: h= 47 inches Mark: h= 70 inches Marissa: h = 28 inches Which ride can every member go on?

See explanation

Step-by-step explanation:

Given

The Swings: h > 24 and h <48

The Twister: h> 42 and h < 60

First, we need to list out the range of values of both ride categories

The Swings: h > 24 and h <48 implies that:

h = 25, 26, 27,28,,47

The twister: h > 42 and h < 60 implies that

h = 43, 44, 45,. 46,, 59

Next, is to compare each height to the height categories above.

Tracey: h= 47 inches

47 inches can be found in both categories; hence, Tracey can ride on the swings and the twister

Mark: h= 70 inches

70 inches is out of range in both categories. Hence, Mark can't ride in any of the ride categories.

Marissa: h = 28 inches

28 inches can be found in the swings category; hence, Marissa can ride on the swings only.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204