I'm BEGGING u pls help... Apply the principles of Kinetic Molecular Theory to graphs of molecular motion This graph represents a population of molecules in a gas versus the distribution of the average velocity (speed) of its molecules in that population. Assume all molecules to be of the same mass. In reading the graph, it is important to note three things. One, is the most probable speed is at the peak of the curve. Secondly, the most probable speed increases as the temperature increases (so shift to the right), and the distribution broadens as it increases.

On the graph, indicate the average kinetic energy of the population at T1 and T2.
Which axis of the graph indicates the temperature of the sample?
Explain your On graph paper sketch a curve that represents the distribution of molecules at a temperature below the one shown. Label it as T3. Describe T1, and T3 in terms of their average kinetic energy. Be specific and detailed.

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

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step-by-step explanation:

10 b/c 5*2 =10

step-by-step explanation: