Solve using quadratic formula 2x^2-64x+494=0

x = 19 or x = 13

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 - 64 x + 494 = 0

Divide both sides by 2:

x^2 - 32 x + 247 = 0

Subtract 247 from both sides:

x^2 - 32 x = -247

Add 256 to both sides:

x^2 - 32 x + 256 = 9

Write the left hand side as a square:

(x - 16)^2 = 9

Take the square root of both sides:

x - 16 = 3 or x - 16 = -3

Add 16 to both sides:

x = 19 or x - 16 = -3

Add 16 to both sides:

x = 19 or x = 13

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9