Which quadratic function in vertex form can be represented by the graph that has a vertex of (3, 7) and passes through the point (1, -10)? A y=−3/4(x+3)2 squared−7
y is equal to negative 3 fourths times open paren x plus 3 close paren squared minus 7

B y=−3/4(x−3)2 squared−7
y is equal to negative 3 fourths times open paren x minus 3 close paren squared minus 7

C y=3/4(x+3)2 squared+7
y is equal to 3 fourths times open paren x plus 3 close paren squared plus 7

D y=3/4(x−3)2 squared+7

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Step-by-step explanation:

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13