16. An object travels along a horizontal straight path at a constant rate. The object travels zo of the length of the path in second. At that rate, how many seconds does it take the object to travel the entire length of the path?

Step-by-step explanation:

Step-by-step explanation:

1/20 is a tiny portion of the length that needs to be traveled.  20/20 is the whole length.  If 1/20 gets traveled in 3/4 of a second, multiply 3/4 by 20 to see how long it takes to travel 20(1/20) which is equal to 1, the whole path.

20(3/4) = 15 seconds

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1