An airplane left the airport in Nevada and traveled 3200.0 km to LA. The airplane had an average velocity of 222 m/s. How long was the flight from Nevada to LA in seconds. I will reward brainliest if right. Please and thank you.

Step-by-step explanation:

plane traveled 3200 km

aver. velocity = 222 m/s

find:

How long was the flight from Nevada to LA in seconds.

solution:

time = distance / velocity

       =   3200 km    x     1000 m    

               222 m/s            1 km

        =  14,414.41 seconds

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1